POJ2584_T-Shirt Gumbo(二分圖多重最大匹配/最大流)
阿新 • • 發佈:2017-05-15
make sdn iss ... spa scanf ams ipp char s
解題報告
http://blog.csdn.net/juncoder/article/details/38239367
題目傳送門
題意:
X個參賽選手,每一個選手有衣服大小的範圍,5種大小的隊服,求能否使每一個選手都拿到符合自己大小範圍的衣服。
思路:
X人5種衣服,有的人選的衣服可能大小一樣,這樣就是二分圖的多重最大匹配。源點到5種衣服的容量就是衣服的數量。
#include <queue> #include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #define inf 99999999 using namespace std; int n,mmap[30][30],m,l[30],t; int T_shirt[30]; int bfs() { queue<int >Q; Q.push(0); memset(l,-1,sizeof(l)); l[0]=0; while(!Q.empty()) { int u=Q.front(); Q.pop(); for(int i=0; i<=m; i++) { if(l[i]==-1&&mmap[u][i]) { l[i]=l[u]+1; Q.push(i); } } } if(l[m]>1)return 1; else return 0; } int dfs(int x,int f) { int a; if(x==m)return f; for(int i=0; i<=m; i++) { if(mmap[x][i]&&l[i]==l[x]+1&&(a=dfs(i,min(f,mmap[x][i])))) { mmap[x][i]-=a; mmap[i][x]+=a; return a; } } l[x]=-1; return 0; } int main() { int i,j; char str[100]; char s[10]; T_shirt['S'-'A']=1; T_shirt['M'-'A']=2; T_shirt['L'-'A']=3; T_shirt['X'-'A']=4; T_shirt['T'-'A']=5; while(cin>>str) { memset(mmap,0,sizeof(mmap)); if(!strcmp(str,"ENDOFINPUT")) break; if(!strcmp(str,"END")) continue; cin>>n; m=n+5+1; for(i=1; i<=n; i++) { cin>>s; int a=T_shirt[s[0]-'A']; int b=T_shirt[s[1]-'A']; if(a>b) swap(a,b); for(j=a; j<=b; j++) { mmap[j][i+5]=1; } mmap[i+5][m]=1; } for(i=1; i<=5; i++) { scanf("%d",&t); mmap[0][i]=t; } int ans=0; cin>>str; while(bfs()) while(t=dfs(0,inf)) ans+=t; if(ans==n) cout<<"T-shirts rock!"<<endl; else cout<<"I'd rather not wear a shirt anyway..."<<endl; if(!strcmp(str,"END"))continue; } return 0; }
T-Shirt Gumbo
Description Boudreaux and Thibodeaux are student volunteers for this year‘s ACM South Central Region‘s programming contest. One of their duties is to distribute the contest T-shirts to arriving teams. The T-shirts had to be ordered in advance using an educated guess as to how many shirts of each size should be needed. Now it falls to Boudreaux and Thibodeaux to determine if they can hand out T-shirts to all the contestants in a way that makes everyone happy.Input A single data set has 4 components:
After the last data set, there will be a single line: ENDOFINPUT Output For each data set, there will be exactly one line of output. This line will reflect the attitude of the contestants after the T-shirts are distributed. If all the contestants were satisfied, output:T-shirts rock! Otherwise, output: I‘d rather not wear a shirt anyway... Sample Input START 1 ST 0 0 1 0 0 END START 2 SS TT 0 0 1 0 0 END START 4 SM ML LX XT 0 1 1 1 0 END ENDOFINPUT Sample Output T-shirts rock! I‘d rather not wear a shirt anyway... I‘d rather not wear a shirt anyway... Source field=source&key=South+Central+USA+2003" style="text-decoration:none">South Central USA 2003 |
POJ2584_T-Shirt Gumbo(二分圖多重最大匹配/最大流)