使用SUM函數，加上GROUP BY人員ID就可以實現了：

SELECT SUM(PZ+CPJS+BZ+GC+SB+TG+MJ+CL+CCLW+GJ+ZL+CBZZ) as count,
    SUM(PZ) as PZ,SUM(CPJS) as CPJS,SUM(BZ) as BZ,SUM(GC) as GC,SUM(SB) as SB,SUM(TG) as TG,SUM(MJ) as MJ,SUM(CL) as CL,SUM(CCLW) as CCLW,SUM(GJ) as GJ,SUM(ZL) as ZL,SUM(CBZZ) as CBZZ,SUM(YHID) as YHID,SUM(DJRMC) as DJRMC FROM tableName WHERE YHID=‘$ID‘ AND NF=‘$NF‘ GROUP BY YHID;

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