4、Hint:（1）urllib可能會有幫助。不要嘗試一直循環，停不下來。400次就已經足夠了

　　　 （2）www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345

進入鏈接之後會提示下一個nothing=的值

用urllib庫和re庫 類似於爬蟲

# -*- coding:UTF-8 -*-

from urllib import request
import re

def findURL(x):
    while x.isdigit():
        url = ‘http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=
 
‘+x
        print(url)
        response = request.urlopen(url)
        html = response.read()
        html = html.decode(‘utf-8‘)
        print(html)
        replacetext = re.findall(r‘[0-9]‘, str(html))
        print(replacetext)
        x = "".join(replacetext)
    return html

if __name__ == ‘__main__
 
‘:
    findURL(‘12345‘)
    findURL(‘8022‘)

中間會有一個頁面內容是：Yes. Divide by two and keep going.

只好包裝成函數然後再繼續運行

最後答案是peak.html

pythonchallenge闖關 第4題