LeetCode 406: Queue Reconstruction

阿新 • • 發佈：2017-10-08

return [] turn list .so [0 etc class const

This is SO AWESOME solution.

class Solution {
    public int[][] reconstructQueue(int[][] people) {
        Arrays.sort(people, (p1, p2) -> p1[0] != p2[0] ? p2[0] - p1[0] : p1[1] - p2[1]);
        List<int[]> result = new ArrayList<>();
        for (int[] p : people) {
            result.add(p[ 
1], p);
        }
        return result.toArray(new int[people.length][]);
    }
}

[leetcode-406-Queue Reconstruction by Height]

pytho pos line and sin solution ont input concise Suppose you have a random list of people standing in a queue. Each person is described

LeetCode 406: Queue Reconstruction

return [] turn list .so [0 etc class const This is SO AWESOME solution. class Solution { public int[][] reconstructQueue(int[][] peo

[leetcode] 406.Queue Reconstruction by Height

clas 其中發現可能 etc index stand true eight Suppose you have a random list of people standing in a queue. Each person is described by a pair

python leetcode 406. Queue Reconstruction by Height

要儘量保證大的h在後面所以進行如下 people = sorted(people, key=lambda people:(-people[0],people[1])) h降序 k降序再遍歷進行插入操作，插入位置為people[i][1]能保證符合題意舉例說明 people=[[7,0]

leetcode:(406)Queue Reconstruction by Height(java)

題目： Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k),

[Leetcode] 406. Queue Reconstruction by Height 直覺解釋

406. Queue Reconstruction by Height https://leetcode.com/problems/queue-reconstruction-by-height/ 首先，我們找到最小的 height (h, k)，這個資料對的最終位置應該是在 k +

Leetcode 406. Queue Reconstruction by Height[Medium]

原題地址題目內容題目分析題目的主要意思為，給你一串陣列，讓你對其進行“排序”，每個元素由兩個值構成(a,b)，a代表這個字元的大小，b代表有多少個比他大或者等於他的數字排在他前面，這就是最後生成的陣列需要滿足的條件。首先我們可以對陣列按照a進行從大到小的排序，如果

leetcode:406. Queue Reconstruction by Height

Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers(h, k), where h is the height of the person and

[LeetCode] 406. Queue Reconstruction by Height

題目 Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is

[LeetCode]406. Queue Reconstruction by Height

[LeetCode]406. Queue Reconstruction by Height 題目描述思路參考了答案解法 people： [[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]] 排序後： [[7,0], [7,1]

LeetCode 406. Queue Reconstruction by Height (依據高度進行佇列重構)

原題 Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of

406. Queue Reconstruction by Height

pre bject err list next return integer leetcode sta Suppose you have a random list of people standing in a queue. Each person is describ

406 Queue Reconstruction by Height 根據身高重建隊列

.com ems end cnblogs 輸出 rand desc 大於 ret 假設有打亂順序的一群人站成一個隊列。每個人由一個整數對(h, k)表示，其中h是這個人的身高，k是排在這個人前面且身高大於或等於h的人數。編寫一個算法來重建這個隊列。註意：總人數少於110

406. Queue Reconstruction by Height的C++解法

先把people按照第一項降序排列(第一項一樣的按第二項升序)。然後重新插入即可。其中要注意的是重寫了sort的比較規則，寫在一個class內需要在函式前加static。 class Solution { public: static bool cmp(pair<

[LeetCode] Queue Reconstruction by Height 根據高度重建佇列

Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers(h, k), where h is the height of the person a