第三次作業 結對編程
阿新 • • 發佈:2017-10-23
完成 需要 ges swe scanf style 基礎 退出 第三次作業
{
static char panduanjieguo[30];
FILE * in ,* out,* cuoti;
in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&eright,&ewrong);
fclose(in);
if(strcmp(shuru,edaan)==0)
{
strcpy(panduanjieguo,"Right!");
eright++;
}
else
{
strcpy(panduanjieguo,"wrong!");
strcat(panduanjieguo,"Answer is:");
strcat(panduanjieguo,edaan);
ewrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s wrong!Right answer is %s\n",timu,shuru,edaan);
fclose(cuoti);
}
out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",eright,ewrong);
fclose(out);
return panduanjieguo;
}
char * daanpanduan(char daan[],char * shuru,char *timu)
{
static char panduanjieguo[20];
FILE * in ,* out,* cuoti;
in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&right,&wrong);
fclose(in);
if(strcmp(shuru,daan)==0)
{
strcpy(panduanjieguo,"回答正確!!!!");
right++;
}
else
{
strcpy(panduanjieguo,"錯誤!");
strcat(panduanjieguo,"正確答案為:");
strcat(panduanjieguo,daan);
wrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s 錯誤!正確答案為%s\n",timu,shuru,daan);
fclose(cuoti);
}
out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",right,wrong);
fclose(out);
return panduanjieguo;
}
結對編程1 四則運算
201421122075 郭曉迪
201421122089 曾瑞
需求分析:
思維導圖
代碼展示
中英文對比
char * edaanpanduan(char daan[],char * shuru,char * timu)
{
static char panduanjieguo[30];
FILE * in ,* out,* cuoti;
in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&eright,&ewrong);
fclose(in);
if(strcmp(shuru,edaan)==0)
{
strcpy(panduanjieguo,"Right!");
eright++;
}
else
{
strcpy(panduanjieguo,"wrong!");
strcat(panduanjieguo,"Answer is:");
strcat(panduanjieguo,edaan);
ewrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s wrong!Right answer is %s\n",timu,shuru,edaan);
fclose(cuoti);
}
out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",eright,ewrong);
fclose(out);
return panduanjieguo;
}
char * daanpanduan(char daan[],char * shuru,char *timu)
{
static char panduanjieguo[20];
FILE * in ,* out,* cuoti;
in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&right,&wrong);
fclose(in);
if(strcmp(shuru,daan)==0)
{
strcpy(panduanjieguo,"回答正確!!!!");
right++;
}
else
{
strcpy(panduanjieguo,"錯誤!");
strcat(panduanjieguo,"正確答案為:");
strcat(panduanjieguo,daan);
wrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s 錯誤!正確答案為%s\n",timu,shuru,daan);
fclose(cuoti);
}
out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",right,wrong);
fclose(out);
return panduanjieguo;
}
程序運行
小結感受
結對編程需要好好進行分工,從而才能好好團結協作,以1+1>2的效率完成工作。
評價夥伴
略。
PSP.
第三次作業 結對編程