# 元組[有序不變序列](不可修改)
def tuples():
    # --- 元組 ---
    # 創建 (類似於列表的數據存儲方式,但是不能修改)
    tuples = ("柳巖", 21, "女")
    tuples = tuple(["a", "b", "c"]) # 將 列表 轉為 元組 (註:將字典轉為元組會損失數據)
    tuples = tuple() # 空元組,不知何用

    # × 添加 × 修改 × 刪除 (註意:不許修改)

    # 獲取
    tuples = ("柳巖", 21, "女")
    strs = tuples[0] # 獲取指定索引數據, ‘柳巖‘
    strs = tuples[-1] # 倒數獲取數據 (1開始), ‘女‘
    tup4 = tuples[1:] # 截取, <class ‘tuple‘>: (21, ‘女‘)
    tup5 = tuples[0:2] # <class ‘tuple‘>: (‘柳巖‘, 21)
    tup2 = tuples + (1, 2, 3) # 合並元組(原元組不變), <class ‘tuple‘>: (‘柳巖‘, 21, ‘女‘, 1, 2, 3)
    tup3 = tuples * 3 # 復制(3份)合並元組, <class ‘tuple‘>: (‘柳巖‘, 21, ‘女‘, ‘柳巖‘, 21, ‘女‘, ‘柳巖‘, 21, ‘女‘)
    strs = max((1, 3, 6, 2.5)) # 最大值, 6
    strs = min((1, 3, 6, 2.5))

    # 統計
    length = len(tuples) # 元組長度
    count = tuples.count(21) # 該元素的數量

 

# 查找
index = tuples.index(21) # 該元素出現的索引,找不到拋異常
index = tuples.index(21, 1) # 從 1-末尾
index = tuples.index(21, 0, 2) # 從 0-2

# 遍歷
for i in tuples:
    print("tuple:%s"%i)

# 判斷
boolean = 21 in tuples
boolean = 21 not in tuples

Python3-筆記-B-003-數據結構-元組tuple( )