偶數求1/2+1/4+...+1/n奇數1/1+1/3+...+1/n
阿新 • • 發佈:2017-12-20
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題目:編寫一個函數,輸入n為偶數時,調用函數求1/2+1/4+...+1/n,當輸入n為奇數時,調用函數1/1+1/3+...+1/n
Scanner scanner = new Scanner(System.in); int num = scanner.nextInt(); double sum = 0; if (num%2!=0) { for (int i = 1; i <= num; i=i+2) { sum += 1.0/i; System.out.print(1+"/"+i+"\t"); System.out.print(1.0/i+"\t"); System.out.println(""); } }else { for (int i = 2; i <= num; i=i+2) { sum += 1.0/i; System.out.print(1+"/"+i+"\t"); System.out.print(1.0/i+"\t"); System.out.println(""); } } System.out.println(sum);
源碼
偶數求1/2+1/4+...+1/n奇數1/1+1/3+...+1/n