編程之路:MySql系列之多表查詢
阿新 • • 發佈:2018-05-11
所有 連接 進行 查看 bsp 關鍵字 right emp 字段
多表連接查詢
#重點:外鏈接語法 SELECT 字段列表 FROM 表1 INNER|LEFT|RIGHT JOIN 表2 ON 表1.字段 = 表2.字段;
交叉連接:不適用任何匹配條件。生成笛卡爾積
mysql> select * from employee,department; +----+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +----+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技術 | | 1 | egon | male | 18 | 200 | 201 | 人力資源 | | 1 | egon | male | 18 | 200 | 202 | 銷售 | | 1 | egon | male | 18 | 200 | 203 | 運營 | | 2 | alex | female | 48 | 201 | 200 | 技術 | | 2 | alex | female | 48 | 201 | 201 | 人力資源 | | 2 | alex | female | 48 | 201 | 202 | 銷售 | | 2 | alex | female | 48 | 201 | 203 | 運營 | | 3 | wupeiqi | male | 38 | 201 | 200 | 技術 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力資源 | | 3 | wupeiqi | male | 38 | 201 | 202 | 銷售 | | 3 | wupeiqi | male | 38 | 201 | 203 | 運營 | | 4 | yuanhao | female | 28 | 202 | 200 | 技術 | | 4 | yuanhao | female | 28 | 202 | 201 | 人力資源 | | 4 | yuanhao | female | 28 | 202 | 202 | 銷售 | | 4 | yuanhao | female | 28 | 202 | 203 | 運營 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技術 | | 5 | liwenzhou | male | 18 | 200 | 201 | 人力資源 | | 5 | liwenzhou | male | 18 | 200 | 202 | 銷售 | | 5 | liwenzhou | male | 18 | 200 | 203 | 運營 | | 6 | jingliyang | female | 18 | 204 | 200 | 技術 | | 6 | jingliyang | female | 18 | 204 | 201 | 人力資源 | | 6 | jingliyang | female | 18 | 204 | 202 | 銷售 | | 6 | jingliyang | female | 18 | 204 | 203 | 運營 | +----+------------+--------+------+--------+------+--------------+
內連接:只連接匹配的行
#找兩張表共有的部分,相當於利用條件從笛卡爾積結果中篩選出了正確的結果 #department沒有204這個部門,因而employee表中關於204這條員工信息沒有匹配出來 mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id; +----+-----------+------+--------+--------------+ | id | name | age | sex | name | +----+-----------+------+--------+--------------+ | 1 | egon | 18 | male | 技術 | | 2 | alex | 48 | female | 人力資源 | | 3 | wupeiqi | 38 | male | 人力資源 | | 4 | yuanhao | 28 | female | 銷售 | | 5 | liwenzhou | 18 | male | 技術 | +----+-----------+------+--------+--------------+ #上述sql等同於 mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department where employee.dep_id=department.id;
外鏈接之左連接:優先顯示左表全部記錄
#以左表為準,即找出所有員工信息,當然包括沒有部門的員工 #本質就是:在內連接的基礎上增加左邊有右邊沒有的結果 mysql> select employee.id,employee.name,department.name as depart_name fromemployee left join department on employee.dep_id=department.id; +----+------------+--------------+ | id | name | depart_name | +----+------------+--------------+ | 1 | egon | 技術 | | 5 | liwenzhou | 技術 | | 2 | alex | 人力資源 | | 3 | wupeiqi | 人力資源 | | 4 | yuanhao | 銷售 | | 6 | jingliyang | NULL | +----+------------+--------------+
外鏈接之右連接:優先顯示右表全部記錄
#以右表為準,即找出所有部門信息,包括沒有員工的部門 #本質就是:在內連接的基礎上增加右邊有左邊沒有的結果 mysql> select employee.id,employee.name,department.name as depart_name from employee right join department on employee.dep_id=department.id; +------+-----------+--------------+ | id | name | depart_name | +------+-----------+--------------+ | 1 | egon | 技術 | | 2 | alex | 人力資源 | | 3 | wupeiqi | 人力資源 | | 4 | yuanhao | 銷售 | | 5 | liwenzhou | 技術 | | NULL | NULL | 運營 | +------+-----------+--------------+
全外連接:顯示左右兩個表全部記錄
全外連接:在內連接的基礎上增加左邊有右邊沒有的和右邊有左邊沒有的結果 #註意:mysql不支持全外連接 full JOIN #強調:mysql可以使用此種方式間接實現全外連接 select * from employee left join department on employee.dep_id = department.id union select * from employee right join department on employee.dep_id = department.id ; #查看結果 +------+------------+--------+------+--------+------+--------------+ | id | name | sex | age | dep_id | id | name | +------+------------+--------+------+--------+------+--------------+ | 1 | egon | male | 18 | 200 | 200 | 技術 | | 5 | liwenzhou | male | 18 | 200 | 200 | 技術 | | 2 | alex | female | 48 | 201 | 201 | 人力資源 | | 3 | wupeiqi | male | 38 | 201 | 201 | 人力資源 | | 4 | yuanhao | female | 28 | 202 | 202 | 銷售 | | 6 | jingliyang | female | 18 | 204 | NULL | NULL | | NULL | NULL | NULL | NULL | NULL | 203 | 運營 | +------+------------+--------+------+--------+------+--------------+ #註意 union與union all的區別:union會去掉相同的紀錄
符合條件連接查詢
#示例1:以內連接的方式查詢employee和department表,並且employee表中的age字段值必須大於25,即找出年齡大於25歲的員工以及員工所在的部門 select employee.name,department.name from employee inner join department on employee.dep_id = department.id where age > 25; #示例2:以內連接的方式查詢employee和department表,並且以age字段的升序方式顯示 select employee.id,employee.name,employee.age,department.name from employee,department where employee.dep_id = department.id and age > 25 order by age asc;
子查詢
#1:子查詢是將一個查詢語句嵌套在另一個查詢語句中。 #2:內層查詢語句的查詢結果,可以為外層查詢語句提供查詢條件。 #3:子查詢中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等關鍵字 #4:還可以包含比較運算符:= 、 !=、> 、<等
帶IN關鍵字的子查詢
#查詢平均年齡在25歲以上的部門名 select id,name from department where id in (select dep_id from employee group by dep_id having avg(age) > 25); #查看技術部員工姓名 select name from employee where dep_id in (select id from department where name=‘技術‘); #查看不足1人的部門名(子查詢得到的是有人的部門id) select name from department where id not in (select distinct dep_id from employee);
帶比較運算符的子查詢
#比較運算符:=、!=、>、>=、<、<=、<> #查詢大於所有人平均年齡的員工名與年齡 mysql> select name,age from emp where age > (select avg(age) from emp); +---------+------+ | name | age | +---------+------+ | alex | 48 | | wupeiqi | 38 | +---------+------+ rows in set (0.00 sec) #查詢大於部門內平均年齡的員工名、年齡 select t1.name,t1.age from emp t1 inner join (select dep_id,avg(age) avg_age from emp group by dep_id) t2 on t1.dep_id = t2.dep_id where t1.age > t2.avg_age;
帶EXISTS關鍵字的子查詢
EXISTS關字鍵字表示存在。在使用EXISTS關鍵字時,內層查詢語句不返回查詢的記錄。
而是返回一個真假值。True或False
當返回True時,外層查詢語句將進行查詢;當返回值為False時,外層查詢語句不進行查詢
#department表中存在dept_id=203,Ture mysql> select * from employee -> where exists -> (select id from department where id=200); +----+------------+--------+------+--------+ | id | name | sex | age | dep_id | +----+------------+--------+------+--------+ | 1 | egon | male | 18 | 200 | | 2 | alex | female | 48 | 201 | | 3 | wupeiqi | male | 38 | 201 | | 4 | yuanhao | female | 28 | 202 | | 5 | liwenzhou | male | 18 | 200 | | 6 | jingliyang | female | 18 | 204 | +----+------------+--------+------+--------+ #department表中存在dept_id=205,False mysql> select * from employee -> where exists -> (select id from department where id=204); Empty set (0.00 sec)
編程之路:MySql系列之多表查詢