java編程思想-第13章-某些練習題
阿新 • • 發佈:2018-05-22
運行 ngs als ack mat tool spa replace color
. 匹配任意一個字符
* 表示匹配0個或多個前面這個字符
+ 表示1個或多個前面這個字符
? 表示0個或1個前面這個字符
^ 表示一行的開始 ^[a-zA-Z] :表示開頭是a-z或者A-Z
[^0-9] :表示不是數字,除數字以外的
$ 表示一行的結束
第七題:
package net.mindview.strings.test7;
public class Test7 {
public static void main(String[] args) {
//兩種寫法都可以
String regex = "^[A-Z].*\\.$";//"^[A-Z].*\\."這樣也對
String regex1 = "\\p{Upper}.*\\.$";
String str = "D.";
String str1 = "Dfasdfasfasfdasfdasfasfasdf.";
String str2 = "Dfasdfasfasfdasfdasfasfasdf.E";
System.out.println(str.matches(regex));
System.out.println(str1.matches(regex));
System.out.println(str2.matches(regex));
System.out.println(str.matches(regex1));
System.out.println(str1.matches(regex1));
System.out.println(str2.matches(regex1));
}
}
運行結果:
truetrue
false
true
true
false
第八題
package net.mindview.strings;
import java.util.Arrays;
public class Splitting {
public static String knights = "Then, when you have found the shrubbery, you must cut down the mightiest tree in the forest... with... a herring!";
public static void split(String regex){
System.out.println(Arrays.toString(knights.split(regex)));
}
public static void main(String[] args) {
//表示的時按照空格分割字符串
//運行結果:[Then,, when, you, have, found, the, shrubbery,, you, must, cut, down, the, mightiest, tree, in, the, forest..., with..., a, herring!]
split(" ");
//表示按照非單次字符分割字符串--這裏的非單次字符是空格和,
//運行結果:[Then, when, you, have, found, the, shrubbery, you, must, cut, down, the, mightiest, tree, in, the, forest, with, a, herring]
split("\\W+");
//這個表示:費單次字符之前帶n的地方進行分割字符串 這裏的分割符是n空格和n,
//運行結果:[The, whe, you have found the shrubbery, you must cut dow, the mightiest tree i, the forest... with... a herring!]
split("n\\W+");
}
}
package net.mindview.strings.test8;
import net.mindview.strings.Splitting;
public class Test8 {
public static void main(String[] args) {
String regex = "the|you";
Splitting.split(regex);
}
}
第九題
package net.mindview.strings.test9;
import net.mindview.strings.Splitting;
public class Test9 {
public static void main(String[] args) {
String regex = "A|E|I|O|U|a|e|i|o|u";
//通過嵌入式標誌表達式 (?i) 也可以啟用不區分大小寫的匹配。
String regex1 = "(?i)a|e|i|o|u";
//[abc] 表示a或b或c
String regex2 = "(?i)[aeiou]";
System.out.println(Splitting.knights.replaceAll(regex, "_"));
System.out.println(Splitting.knights.replaceAll(regex1, "_"));
System.out.println(Splitting.knights.replaceAll(regex2, "_"));
}
}
java編程思想-第13章-某些練習題