#include<stdio.h>
int A[110];
int main() {
    int n, m, temp;
    scanf("%d%d", &n, &m);
    m = m % n;
    for (int i = 0; i < n; i++) {
        scanf("%d", &A[i]);
    }
    for (int i = n - m; i < n; i++) {
        printf("%d ", A[i]);
    }
    for (int i = 0; i < n - m - 1
 
; i++) {
        printf("%d ", A[i]);
    }
    printf("%d", A[n - m - 1]);
    return 0;
}   

其他方法參考：

http://www.cnblogs.com/asheng2016/p/7661311.html

https://blog.csdn.net/xtzmm1215/article/details/38407799

B1008 數組元素循環右移問題 (20)