C++中char類型的十六進制字符串轉換成字節流
阿新 • • 發佈:2018-06-06
toupper 14. 轉換成 urn 類型 else con src for
如a[5]="1234"轉換成a[5]={0x12,0x34}
代碼如下:
void HexStrToByte(const char* source, unsigned char* dest, int sourceLen)
{
short i;
unsigned char highByte, lowByte;
for (i = 0; i < sourceLen; i += 2)
{
highByte = toupper(source[i]);
lowByte = toupper(source[i + 1]);
if (highByte > 0x39)
highByte -= 0x37;
else
highByte -= 0x30;
if (lowByte > 0x39)
lowByte -= 0x37;
else
lowByte -= 0x30;
dest[i / 2] = (highByte << 4) | lowByte;
}
return ;
}
int main(void)
{
BYTE bufASC[1024]={0};
char ha[7] = "ef2233";
unsigned char temp[200]={0};
HexStrToByte(ha,temp,6);
C++中char類型的十六進制字符串轉換成字節流