leetcode 226. Invert Binary Tree

阿新 • • 發佈：2018-09-17

bin spa clas node == span rtt binary solution

class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        if(root == NULL)
            return NULL;
        TreeNode* tmp = invertTree(root->left);
        root->left = invertTree(root->right);
        root->right = tmp;
        return root;
    }
};

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leetcode 226. Invert Binary Tree

bin spa clas node == span rtt binary solution class Solution { public: TreeNode* invertTree(TreeNode* root) { if(root == N

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這道題很簡單了，只需要遞迴的交換左右子樹就好了 class Solution { public TreeNode invertTree(TreeNode root) { helper(root); return root

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