最小公倍數

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 69793 Accepted Submission(s): 38394

代碼:

 1 #include<stdio.h>
 2 int fun(int a,int b){
 3     if(a%b==0)
 4         return b;
 5     else
 6         return fun(b,a%b);
 7 }
 8 int main(){
 9     int a,b,ans;
10     while(~scanf("%d%d",&a,&b)){
11         ans=a*b/fun(a,b);
 
12         printf("%d\n",ans);
13     }
14         return 0;
15 }

HDU 1108.最小公倍數-輾轉相除法