形如這樣的多元函式，求[x1,x2]區間的積分。即求解的值。java程式碼如下：

這裡寫程式碼片public class MulFunctionIntegral {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner sc=new Scanner(System.in);
        System.out.println("輸入a的值:");
        int a=sc.nextInt();
        System.out
 
.println("輸入b的值:");
        int b=sc.nextInt();
        System.out.println("輸入c的值:");
        int c=sc.nextInt();
        System.out.println("輸入n的值:");
        int n=sc.nextInt();
        System.out.println("輸入m的值:");
        int m=sc.nextInt();
        System.out.println("輸入x1的值:");
        double x1=sc.nextDouble();
        System.out
 
.println("輸入x2的值:");
        double x2=sc.nextDouble();
        double value=Integral(a,b,c,n,m,x1,x2);

    }
    public static double Integral(int a,int b,int c,int n,int m,double x1,double x2){
        double y1=a/(n+1)*Math.pow(x1, n+1)+b/(m+1)*Math.pow(x1, m+1)+c*x1;
        double y2=a/(n+1)*Math.pow(x2, n+1
 
)+b/(m+1)*Math.pow(x2, m+1)+c*x2;
        double y=y2-y1;
        return y;
    }