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題解:UVA10298 Power Strings

求解每個字串的最短迴圈子串

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
const int maxn=1000005;
int p[maxn];
char a[maxn];
int n;
void init(){
    int j=0;
    p[1]=0;
    for(int i=2; i<=n; i++){
        while(j && a[j+1]!=a[i]) j=p[j];
        
if(a[i]==a[j+1]) j++; p[i]=j; } } int main(){ for(;;){ scanf("%s",a+1); if(a[1]=='.') break; n=strlen(a+1); init(); if(n%(n-p[n])==0) printf("%d\n",n/(n-p[n])); else printf("1\n"); } return 0; }