c++ 查詢容器中不滿足條件的元素,返回iterator(find_if_not)
阿新 • • 發佈:2018-11-08
#include <iostream> // std::cout #include <algorithm> // std::find_if_not #include <array> // std::array using namespace std; int main () { array<int,5> foo = {1,2,3,4,5}; array<int,5>::iterator it =find_if_not (foo.begin(), foo.end(), [](int i){returni%2;} ); //偶數就為假 cout << "The first even value is " << *it << '\n'; return 0; }