Difficulty

Easy.

Problem

Given a binary tree, return the bottom-up level order traversal of its nodes' values. 
(ie, from left to right, level by level from leaf to root).

For example:
Given binary tree [3,9,20,null,null,15,7],
    3
   / \
  9  20
    /  \
   15   7
return its bottom-up level order traversal as
 
:
[
  [15,7],
  [9,20],
  [3]
]

AC

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None


# BFS
class Solution():
    def levelOrderBottom(self, root):
        res = []
        if
 
 root:
            level = [root]
            while len(level):
                res = [[node.val for node in level]] + res
                tmp = []
                for node in level:
                    if node.left:
                        tmp.append(node.left)
                    if node.right:
                        tmp.
 
append(node.right)
                level = tmp
        return res