用python快速製作xml檔案

Shawn
python 3.7

• 因為工作需要, 要用到xml檔案,所以用python寫了個類,以實現快速製作xml檔案.

from xml.dom.minidom import Document
# import xml.dom.minidom

class XmlMaker:


    def __init__(self,txtpath,xmlpath):
        self.txtPath = txtpath
        self.xmlPath = xmlpath
        self.
 
txtList = []


    def readtxt(self):
        txtfile = open(self.txtPath,"r",encoding='gbk',errors='ignore')
        self.txtList = txtfile.readlines()
        for i in self.txtList:
            oneline = i.strip().split(" ")
            if len(oneline) != 5:
                print("TxtError")

    def
 
 makexml(self):
        doc = Document()
        orderpack = doc.createElement("OrderPack")
        doc.appendChild(orderpack)
        objecname = "Order"
        for i in self.txtList:
            oneline = i.strip().split(" ")
            objectE = doc.createElement(objecname)
            objectE.
 
setAttribute("number",oneline[0])

            objectcontent = doc.createElement("Content")
            objectcontenttext = doc.createTextNode(oneline[1])
            objectcontent.appendChild(objectcontenttext)
            objectE.appendChild(objectcontent)

            objectresult = doc.createElement("Result")
            objectresulttext = doc.createTextNode(oneline[2])
            objectresult.appendChild(objectresulttext)
            objectE.appendChild(objectresult)

            objectappname = doc.createElement("AppName")
            objectappnametext = doc.createTextNode(oneline[3])
            objectappname.appendChild(objectappnametext)
            objectE.appendChild(objectappname)

            objectdelay = doc.createElement("Delay")
            objectdelaytext = doc.createTextNode(oneline[4])
            objectdelay.appendChild(objectdelaytext)
            objectE.appendChild(objectdelay)

            orderpack.appendChild(objectE)

        f = open(self.xmlPath, 'w')
        doc.writexml(f, indent='\t', newl='\n', addindent='\t', encoding='gbk')
        f.close()



if __name__ == "__main__":
    read =XmlMaker("test.txt","test.xml")
    read.readtxt()
    read.makexml()
    print(read.txtPath)
    for i in read.txtList:
        print(i)

• 過程相當簡單,讀取檔案,然後寫成xml.
• 需要注意的是,python中轉換中文編碼需要小心地選擇編碼模式,而且放在pycharm裡效果可能會更糟糕(亂碼).
• demo 檔案:

0 命令0 結果0 app名0 延遲0
1 命令1 結果1 app名1 延遲1
2 命令2 結果2 app名2 延遲2
3 命令3 結果3 app名3 延遲3
4 命令4 結果4 app名4 延遲4
5 命令5 結果5 app名5 延遲5

• 生成結果:

<?xml version="1.0" encoding="gbk"?>
	<OrderPack>
		<Order number="0">
			<Content>命令0</Content>
			<Result>結果0</Result>
			<AppName>app名0</AppName>
			<Delay>延遲0</Delay>
		</Order>
		<Order number="1">
			<Content>命令1</Content>
			<Result>結果1</Result>
			<AppName>app名1</AppName>
			<Delay>延遲1</Delay>
		</Order>
		<Order number="2">
			<Content>命令2</Content>
			<Result>結果2</Result>
			<AppName>app名2</AppName>
			<Delay>延遲2</Delay>
		</Order>
		<Order number="3">
			<Content>命令3</Content>
			<Result>結果3</Result>
			<AppName>app名3</AppName>
			<Delay>延遲3</Delay>
		</Order>
		<Order number="4">
			<Content>命令4</Content>
			<Result>結果4</Result>
			<AppName>app名4</AppName>
			<Delay>延遲4</Delay>
		</Order>
		<Order number="5">
			<Content>命令5</Content>
			<Result>結果5</Result>
			<AppName>app名5</AppName>
			<Delay>延遲5</Delay>
		</Order>
	</OrderPack>