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用Java8把List轉為Map

 1 import com.yang.test.User;
 2  
 3 import javax.jws.soap.SOAPBinding;
 4 import java.util.*;
 5 import java.util.function.Function;
 6 import java.util.stream.Collectors;
 7  
 8 public class Main {
 9  
10     public static void main(String[] args) {
11  
12         List<User> userlist = new
ArrayList<>(); 13 for (int i = 0; i <10; i++) { 14 15 userlist.add(new User("張三"+i,i)); 16 } 17 System.out.println(getAllages(userlist).size()); 18 19 System.out.println(getUser2Map(userlist)); 20 21 System.out.println(getUser2MapUser(userlist));
22 23 System.out.println(getUser2MapUser2(userlist)); 24 25 System.out.println(getUser2MapUser3(userlist)); 26 27 } 28 29 public static List<Integer> getAllages(List<User>userlist){ 30 return userlist.stream().map(user -> user.getAge()).collect(Collectors.toList());
31 } 32 33 public static Map<Integer,String> getUser2Map(List<User>userlist){ 34 35 return userlist.stream().collect(Collectors.toMap(User::getAge,User::getName)); 36 } 37 38 public static Map<Integer,User> getUser2MapUser(List<User>userlist){ 39 40 return userlist.stream().collect(Collectors.toMap(User::getAge,User-> User)); 41 } 42 43 /** 44 * 比較優雅的寫法是這樣的 45 * @param userlist 46 * @return 47 */ 48 public static Map<Integer,User> getUser2MapUser2(List<User>userlist){ 49 50 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity())); 51 } 52 53 /** 54 * 重複key的情況下 簡單的使用後者覆蓋前者的 55 */ 56 public static Map<Integer,User> getUser2MapUser3(List<User>userlist){ 57 58 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2)); 59 } 60 61 /** 62 *指定map的具體實現 63 * @param userlist 64 * @return 65 */ 66 public static Map<Integer,User> getUser2MapUser4(List<User>userlist){ 67 68 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2, LinkedHashMap::new)); 69 } 70 }