題目

Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer n and then they take turns, starting from Mahmoud. In each player’s turn, he has to choose an integer a and subtract it from n such that:

1,1 ≤ a ≤ n.
2,If it’s Mahmoud’s turn, a has to be even, but if it’s Ehab’s turn, a has to be odd.

If the current player can’t choose any number satisfying the conditions, he loses. Can you determine the winner if they both play optimally?

Input

The only line contains an integer n (1 ≤ n ≤ 109), the number at the beginning of the game.

Output

Output “Mahmoud” (without quotes) if Mahmoud wins and “Ehab” (without quotes) otherwise.

Examples

input

1

output

Ehab

input

2

output

Mahmoud

Note

In the first sample, Mahmoud can’t choose any integer a initially because there is no positive even integer less than or equal to 1 so Ehab wins.

In the second sample, Mahmoud has to choose a = 2 and subtract it from n. It’s Ehab’s turn and n = 0. There is no positive odd integer less than or equal to 0 so Mahmoud wins.

題意：

Mahmoud 選擇一個正整數n, Mahmoud和Ehab輪流選擇一個數a（1 ≤ a ≤ n），由Ehab開始，Ehab每次必須選擇一個偶數，Mahmoud每次選擇一個奇數，每次選擇後n=n-a；直到對方無法選擇，則勝利。

解題思路：

巴什博奕思路，當n為偶數是Mahmoud勝利，當n為奇數時，Ehab勝利。

AC-Code

import java.util.Scanner;

public class ACM959A {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		if(n%2==1)
		{
			System.out.println("Ehab");
		}
		else
		{
			System.out.println("Mahmoud");
		}
		sc.close();

	}

}