HDU1231

#include<cstdio>
#include<algorithm>
#include<cstring>
#include<iostream>
#include<cmath>
#include<map>
#include<stack>
#include<vector>
#include<queue>
#include<set>
using namespace std;
const int MAX_N=100005;
#define inf 1<<23
typedef long long ll;
typedef long long LL;
int a[MAX_N];
int n;
int s,e;//記錄開始和結束
void text()
{
    int maxValue=0;
    int thisMaxValue=0;
    for(int i=0;i<n;i++)
    {
        thisMaxValue+=a[i];
        if(thisMaxValue>0)
        {
            maxValue=thisMaxValue>maxValue?thisMaxValue:maxValue;
        }
        else
        {
            thisMaxValue=0;
        }
    }
    printf("%d\n",maxValue);
}
int main()
{
    while(scanf("%d",&n)&&n)
    {
        for(int i=0;i<n;i++)
        {
            scanf("%d",&a[i]);
        }
        text();
    }
    return 0;
}
 

Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14. 
InputThe first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000). 
OutputFor each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases. 
Sample Input

2
5 6 -1 5 4 -7
7 0 6 -1 1 -6 7 -5

Sample Output

Case 1:
14 1 4

Case 2:
7 1 6

#include<cstdio>
#include<algorithm>
#include<cstring>
#include<iostream>
#include<cmath>
#include<map>
#include<stack>
#include<vector>
#include<queue>
using namespace std;
const int MAX_N=100010;
typedef long long ll;
typedef long long LL;
int a[MAX_N];
int n;

void  text(int &res,int &s,int &e)
{
    int maxValue=-(1<<30);
    int thisMaxValue=0;
    int k=1;
    for(int i=0; i<n; i++)
    {
        thisMaxValue+=a[i];
        //cout<< thisMaxValue <<endl;

        if(thisMaxValue>maxValue)
        {
            maxValue=thisMaxValue;
            s=k;
            e=i+1;
        }
        if(thisMaxValue<0)
        {
            thisMaxValue=0;
            k=i+2;
        }
    }
    res=maxValue;
}

int main()
{
    int t;
    int s,e;
    int res;
    scanf("%d",&t);

    for(int j=1; j<=t; j++)
    {
        s=0;
        e=0;
        memset(a,0,sizeof(a));
        scanf("%d",&n);
        for(int i=0; i<n; i++)
        {
            scanf("%d",&a[i]);
        }
        text(res,s,e);
        if(j!=t)
        {
            printf("Case %d:\n",j);
            printf("%d %d %d\n\n",res,s,e);
        }
        else
        {
            printf("Case %d:\n",j);
            printf("%d %d %d\n",res,s,e);
        }
    }

    return 0;
}