資料結構實驗之圖論三:判斷可達性(SDUT 2138)(簡單DFS)
阿新 • • 發佈:2018-11-19
#include <bits/stdc++.h> using namespace std; int gra[1002][1005]; int vis[1002]; int n,m; void dfs(int x) { vis[x] = 1; for(int i = 1; i <= n ; i ++) { if(gra[x][i] == 1 && !vis[i]) { dfs(i); } } } int main() { while(~scanf("%d%d",&n,&m)) { memset(gra,0,sizeof(gra)); memset(vis,0,sizeof(vis)); int u,v; for(int i = 0; i < m; i ++) { scanf("%d %d",&u,&v); gra[u][v] = 1; } dfs(n); if(vis[1] == 1) printf("YES\n"); else printf("NO\n"); } return 0; }