1.依次查詢 最近七天星期幾

select   datename(weekday,getdate()-6) as a,
		 datename(weekday,getdate()-5) as b,
		 datename(weekday,getdate()-4) as c,
		 datename(weekday,getdate()-3) as d,
		 datename(weekday,getdate()-2) as e,
		 datename(weekday,getdate()-1) as f,
		 datename(weekday,getdate()-0) as g
 

查詢結果：

2.根據月份查詢 今天之前的所有資料

with t as (
 select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) date 
 from (select substring(convert(varchar,dateadd(month,-0,getdate()),120),1,7)+'-01' day) t1,
      (select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2  
where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like 
 substring(convert(varchar,dateadd(month,-0,getdate()),120),1,7)+'%')
 select id=ROW_NUMBER()OVER(ORDER BY t1.date),t1.date,
    (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=t1.date) as count ,
    (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=t1.date and voice_state=0) as loseorder ,
    (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=t1.date and voice_state=2) as getorder
 from t t1  where t1.date <= convert(varchar(10),getdate(),23)
 

(查詢上個月convert(varchar,dateadd(month,-1,getdate()),120)）
執行結果：

3.查詢最近一週星期幾 幾號 資料彙總 按倒序

with t as (
select datename(weekday,getdate()- t1.number) weeknum
,substring(convert(varchar,getdate()- t1.number,120),1,11) daynum
 from (select number  from MASTER..spt_values WHERE TYPE='P' AND number >=0 and number <=6  ) t1 )
 select weeknum,daynum,
  (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=daynum) as count ,
  (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=daynum and voice_state=0) as loseorder ,
  (select count(*) from tb_voice_info where substring(convert(varchar,oper_date,120),1,11)=daynum and voice_state=2) as getorder
 from t

 

執行結果：