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10.Json資料交換(傳智播客)

需求:json資料請求並將其輸出

1.controller層開發

//提交json資料並展示
@RequestMapping(value = "/json",method = RequestMethod.POST)
@ResponseBody
public WebResult json(@RequestBody String item){
    WebResult webResult = WebResultHelper.newResult();
    try {
        Items items = JSON.parseObject(item, Items.class);
        webResult.setSuccess(1);
        webResult.put("data",items);
    }catch (Exception e){
        return WebResultHelper.newErrorResult("json串解析錯誤");
    }
    return webResult;
}

2.工具類

public class WebResult implements Serializable {
    private static final long serialVersionUID = 1L;
    private int success;
    private String errorMessage = "";
    private Map<String, Object> result = new HashMap<>();
    public void put(String key, Object value) {
        result.put(key, value);
    }

    public void remove(String key) {
        result.remove(key);
    }
    //get和set方法
}
public class WebResultHelper {
    private WebResultHelper(){}

    public static WebResult newResult(){
        WebResult result = new WebResult();
        result.setSuccess(1);
        return result;
    }

    public static WebResult newErrorResult(String errMessage){
        WebResult result = new WebResult();
        result.setSuccess(0);
        result.setErrorMessage(errMessage);
        return result;
    }
}