可以用字典做 也可以用再加個函式判斷是否是Anagrams

class Solution:
    def findAnagrams(self, s, p):
        """
        :type s: str
        :type p: str
        :rtype: List[int]
        """
        if s=="":
            return []
        res=[]
        lp = len(p)
        ls = len(s)
        if lp > ls:
            return []
        pdict={}
        sdict={}
        for i in range(lp):
            if not p[i] in pdict:
                pdict[p[i]] = 1 
            else:
                pdict[p[i]]+=1 
        for i in range(lp):
            if not s[i] in sdict:
                sdict[s[i]] = 1 
            else:
                sdict[s[i]]+=1 
        i=0
        while i < (ls-lp):
            if pdict == sdict:
                res.append(i)
            
            sdict[s[i]]-=1
            if sdict[s[i]] == 0:
                del sdict[s[i]]
            if not s[i+lp] in sdict:
                sdict[s[i+lp]] = 1 
            else:
                sdict[s[i+lp]]+=1 
            i+=1
        if sdict == pdict:
            res.append(i)
        return res