LeetCode-Easy刷題(28) Pascal's Triangle II
阿新 • • 發佈:2018-12-04
Given an index k, return the kth row of the Pascal's triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
給定一個索引k,返回帕斯卡三角形的第k行。 例如,給定k=3,
僅僅使用O(k)額外空間.
//從後向前 public List<Integer> getRow(int rowIndex) { ArrayList<Integer> cur = new ArrayList<Integer>(); cur.add(1); for (int i = 0; i < rowIndex; i++) { for (int j = cur.size()-1; j >0; j--) { cur.set(j, cur.get(j)+cur.get(j-1)); } cur.add(1); } return cur; }