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PAT (Advanced Level) Practice 1117 Eddington Number (25 分)

二分

#include<cstdio>
using namespace std;

const int N=1e5+5;

int n,a[N];

int check(int x)
{
    int num=0;
    for(int i=1;i<=n;i++)
        if(a[i]>x)
            num++;
    return num>=x;
}

int main()
{
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
        scanf("%d"
,a+i); int l=1,r=n+1; while(l<r) { int mid=(l+r)>>1; if(check(mid)) l=mid+1; else r=mid; } printf("%d\n",l-1); return 0; }