【leetcode日記】2.Add Two Numbers(c語言)
阿新 • • 發佈:2018-12-10
Description:
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example:
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 Explanation: 342 + 465 = 807.
注意邊界: 1.不能將兩個加數從連結串列裡面取出來,加完將和再用連結串列表示,因為這些數可 能會大於int、float、double型的範圍; 2.返回的連結串列,尾巴是否正確指向NULL? 3.推薦測試用例: 0+0=0 5+5=10 9999999991+9=10000000000
struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) {
int num,carry=0,bit;
struct ListNode* p1=l1, *p2=l2;
struct ListNode* l3 = (struct ListNode*)malloc(sizeof(struct ListNode));
num = (p1->val) + (p2->val);
if (num / 10 != 0) carry = 1;
bit = num % 10;
l3->val = bit;
l3->next = NULL;
struct ListNode* p3 = l3;
p1 = p1->next;
p2 = p2->next;
//add
while (p1&&p2)
{
num = (p1->val) + (p2->val)+carry;
carry = 0;
if (num / 10 != 0) carry = 1;
bit = num % 10;
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = bit;
new_node->next = NULL;
p3->next = new_node;
p3 = p3->next;
p1 = p1->next;
p2 = p2->next;
}
if (p1)
{
while (carry != 0&&p1!=NULL)
{
num = (p1->val) + carry;
carry = num / 10;
bit = num % 10;
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = bit;
new_node->next = NULL;
p3->next = new_node;
p3 = p3->next;
p1 = p1->next;
}
if (carry == 0 && p1 == NULL)
{
p3->next = NULL;
return l3;
}
else if (carry == 0)
{
p3->next = p1;
return l3;
}
else if (p1 == NULL)
{
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = 1;
new_node->next = NULL;
p3->next = new_node;
return l3;
}
}
else if (p2)
{
while (carry != 0 && p2 != NULL)
{
num = (p2->val) + carry;
carry = num / 10;
bit = num % 10;
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = bit;
new_node->next = NULL;
p3->next = new_node;
p3 = p3->next;
p2 = p2->next;
}
if (carry == 0 && p2 == NULL)
{
p3->next = NULL;
return l3;
}
else if (carry == 0)
{
p3->next = p2;
return l3;
}
else if (p2 == NULL)
{
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = 1;
new_node->next = NULL;
p3->next = new_node;
return l3;
}
}
else if (carry == 1)
{
struct ListNode* new_node = (struct ListNode*)malloc(sizeof(struct ListNode));
new_node->val = 1;
new_node->next = NULL;
p3->next = new_node;
}
return l3;
}