【python3】leetcode 448. Find All Numbers Disappeared in an Array（easy）
leetcode 448. Find All Numbers Disappeared in an Array（easy）
本來想天秀一把 直接用listcomp語句return
return [i for i in range(1,len(num)+1) if i not in nums]然而超時哈哈哈。。。。:(。。。。
只能拆開寫啦，set之後length會變所以先存一個變數
class Solution: def findDisappearedNumbers(self, nums): """ :type nums: List[int] :rtype: List[int] """ length = len(nums) nums = set(nums) return [i for i in range(1,length+1) if i not in nums]
Runtime: 252 ms, faster than 22.59% of Python3
（現在對執行時間淡定了，一來python本來就沒有c／c++快，而來執行速度好像和網速有點關係，discussion裡的解法自稱很快的在我本地測也不咋快，so。。。找理由不看solution偷Or2）
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