資料庫版本：11.2.0.4

查詢語句：

with force_mathces as
(select l.force_matching_signature mathces,
         max(l.sql_id || l.child_number) max_sql_child,
         dense_rank() over(order by count(*) desc) ranking,count(*) a
    from v$sql l
   where l.force_matching_signature <> 0
     and l.parsing_schema_name <> 'SYS'
   group by l.force_matching_signature
  having count(*) > 10)
select v.sql_id, v.sql_text, v.parsing_schema_name, fm.mathces, fm.ranking,v.force_matching_signature,fm.a
  from force_mathces fm, v$sql v
 where fm.max_sql_child = (v.sql_id || v.child_number)
   and fm.ranking <= 50
 order by fm.ranking;