clc
clear
n = input('請輸入矩陣階數：\n');
for i = 1:n
    fprintf('請輸入矩陣第%d行\n',i);
    A(i,:) = input('');
end
 A
B(:,1) = input('請輸入B向量:\n');
B
for i = 1:n
    x(i) = 0;
    x2(i) = 0;
end
for i =1:4
    for j = 1:n
        for k = 1:n
            if j ~= k
                x(j) = x(j)-A(j,k)*x2(k);
            end
        end
        x(j)=x(j) + B(j);
        x(j)=x(j)/A(j,j);
    end
    x2=x;
    for j = 1:n
        x(j)=0;
    end
    fprintf('第%d次迭代結果：\n',i);
      x2
end