背景：

在運維工作當中常常需要使用零時表進行儲存一些資訊

1.建表語句

CREATE TABLE [dbo].[stu1] (

[sno] int NOT NULL , [name] varchar(255) NULL  ) INSERT INTO [dbo].[stu1] ([sno], [name]) VALUES (N'1', N'tjr1') INSERT INTO [dbo].[stu1] ([sno], [name]) VALUES (N'2', N'tjr2') INSERT INTO [dbo].[stu1] ([sno], [name]) VALUES (N'3', N'frfr')

CREATE TABLE [dbo].[stu2] ( [sno] int NOT NULL , [age] int NULL  ) INSERT INTO [dbo].[stu2] ([sno], [age]) VALUES (N'1', N'1') INSERT INTO [dbo].[stu2] ([sno], [age]) VALUES (N'2', N'2') INSERT INTO [dbo].[stu2] ([sno], [age]) VALUES (N'3', N'3') INSERT INTO [dbo].[stu2] ([sno], [age]) VALUES (N'4', N'4')

如何把兩張表變成如下結果：

SELECT s2.sno,s2.age,s1.name FROM [dbo].[stu2] s2,stu1 s1 where s1.sno=s2.sno

2.into方式插入零時表當中：

SELECT s2.sno,s2.age,s1.name  into #test FROM [dbo].[stu2] s2,stu1 s1 where s1.sno=s2.sno

SELECT * from #test

3.使用update方式插入零時表

drop table #stu create table #stu( sno int, name varchar(50), age int

) INSERT into #stu(sno,name) SELECT sno,name 

from stu1

UPDATE s  set s.age=s2.age  from #stu s   LEFT JOIN stu2 s2 on s.sno=s2.sno

SELECT * from #stu