Java Json和Map互轉
阿新 • • 發佈:2018-12-19
1.Json轉Map
/** * @Author:wangh * @Description:json串解析存至map * @Date: */ public static Map<String, Object> JsonToMap(String jsonStr){ Map<String, Object> map = new HashMap<String, Object>(); JSONObject json = JSONObject.fromObject(jsonStr); for(Object k : json.keySet()){ Object v = json.get(k); if(v instanceof JSONArray){ List<Map<String, Object>> list = new ArrayList<Map<String,Object>>(); Iterator<JSONObject> it = ((JSONArray)v).iterator(); while(it.hasNext()){ JSONObject json2 = it.next(); list.add(JsonToMap(json2.toString())); } map.put(k.toString(), list); } else { map.put(k.toString(), v); } } return map; }
2.Map轉Json
Map<String, TemplateData> param = new HashMap<String, TemplateData>(); param.put("first",new TemplateData("你好,你有新的挪車通知!","#696969")); param.put("keyword1",new TemplateData("測試資訊","#696969")); param.put("keyword2",new TemplateData("10.07","#696969")); param.put("keyword3",new TemplateData("2018-10-10","#696969")); param.put("remark",new TemplateData("我在這兒等著你回來 等著你回來把那車挪開","#696969")); // net.sf.json.JSONObject 將Map轉換為JSON方法 JSONObject json = JSONObject.fromObject(param); System.out.println(json); // org.json.JSONObject 將Map轉換為JSON方法 /*JSONObject json =new JSONObject(param);*/