輸入日期判斷為該年第幾天 （易懂版）
#include<stdio.h>
int main()
{
int i,j,k;
while(scanf("%d/%d/%d",&i,&j,&k) !=EOF){
if((i%4==0 && i%100!=0)||(i%400==0)){
switch(j){
case 1: printf("%d\n",k); break;
case 2: printf("%d\n",31+k); break;
case 3: printf("%d\n",60+k); break;
case 4: printf("%d\n",91+k); break;
case 5: printf("%d\n",121+k); break;
case 6: printf("%d\n",152+k); break;
case 7: printf("%d\n",182+k); break;
case 8: printf("%d\n",213+k); break;
case 9: printf("%d\n",244+k); break;
case 10: printf("%d\n",274+k); break;
case 11: printf("%d\n",305+k); break;
case 12: printf("%d\n",335+k); break;
}
}
else{
switch(j){
case 1: printf("%d\n",k); break;
case 2: printf("%d\n",31+k); break;
case 3: printf("%d\n",60+k-1); break;
case 4: printf("%d\n",91+k-1); break;
case 5: printf("%d\n",121+k-1); break;
case 6: printf("%d\n",152+k-1); break;
case 7: printf("%d\n",182+k-1); break;
case 8: printf("%d\n",213+k-1); break;
case 9: printf("%d\n",244+k-1); break;
case 10: printf("%d\n",274+k-1); break;
case 11: printf("%d\n",305+k-1); break;
case 12: printf("%d\n",335+k-1); break;
}
}
}
return 0;
}
/*
第幾天？
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 73162 Accepted Submission(s): 27675
Problem Description
給定一個日期，輸出這個日期是該年的第幾天。
Input
輸入資料有多組，每組佔一行，資料格式為YYYY/MM/DD組成，具體參見sample input ,另外，可以向你確保所有的輸入資料是合法的。
Output
對於每組輸入資料，輸出一行，表示該日期是該年的第幾天。
Sample Input
1985/1/20
2006/3/12
Sample Output
20
71
*/