Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

class Solution {
    public int reverse(int x) {
        if(x<10 && x>-10)
            return x;
        int max = Integer.MAX_VALUE;
        int min = Integer.MIN_VALUE;
        long verse = 0;
        int remainder = x % 10;
        int sign = 0;
        if(x<=-10){
            x = -x;
            sign = 1;
        }
        while(x > 0){
            remainder = x % 10;
            verse = verse * 10 + remainder;         
            x = x / 10;
        }
        if(verse > max || verse < min)
            return 0;
        if(sign == 1)
            return -(int)verse;
        else
            return (int)verse;
    }
}