轉載自http://blog.163.com/aner_rui/blog/static/12131232820105901451809/

SELECT *
FROM t_info a
WHERE ((SELECT COUNT(*)
          FROM t_info
          WHERE Title = a.Title) > 1)
ORDER BY Title DESC

一。查詢重複記錄

1。查詢全部重複記錄

Select * From 表 Where 重複欄位 In (Select 重複欄位 From 表 Group By 重複欄位 Having Count(*)>1)

2。過濾重複記錄(只顯示一條)

Select * From HZT Where ID In (Select Max(ID) From HZT Group By Title)

注：此處顯示ID最大一條記錄

二。刪除重複記錄

1。刪除全部重複記錄（慎用）

Delete 表 Where 重複欄位 In (Select 重複欄位 From 表 Group By 重複欄位 Having Count(*)>1)

2。保留一條（這個應該是大多數人所需要的 ^_^）

Delete HZT Where ID Not In (Select Max(ID) From HZT Group By Title)

注：此處保留ID最大一條記錄

1、查詢表中多餘的重複記錄，重複記錄是根據單個欄位（peopleId）來判斷

select * from people

where peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)

2、刪除表中多餘的重複記錄，重複記錄是根據單個欄位（peopleId）來判斷，只留有rowid最小的記錄

delete from people

where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)

and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)

3、查詢表中多餘的重複記錄（多個欄位）

select * from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

4、刪除表中多餘的重複記錄（多個欄位），只留有rowid最小的記錄

delete from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查詢表中多餘的重複記錄（多個欄位），不包含rowid最小的記錄

select * from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

補充：

有兩個以上的重複記錄，一是完全重複的記錄，也即所有欄位均重複的記錄，二是部分關鍵欄位重複的記錄，比如Name欄位重複，而其他欄位不一定重複或都重複可以忽略。

1、對於第一種重複，比較容易解決，使用

select distinct * from tableName

就可以得到無重複記錄的結果集。

如果該表需要刪除重複的記錄（重複記錄保留1條），可以按以下方法刪除

select distinct * into #Tmp from tableName

drop table tableName

select * into tableName from #Tmp

drop table #Tmp

發生這種重複的原因是表設計不周產生的，增加唯一索引列即可解決。

2、這類重複問題通常要求保留重複記錄中的第一條記錄，操作方法如下

假設有重複的欄位為Name,Address，要求得到這兩個欄位唯一的結果集

select identity(int,1,1) as autoID, * into #Tmp from tableName

select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID

select * from #Tmp where autoID in(select autoID from #tmp2)

最後一個select即得到了Name，Address不重複的結果集（但多了一個autoID欄位，實際寫時可以寫在select子句中省去此列）