el表示式獲取url中文引數亂碼
1.解決方法：改變tomcat檔案server.xml標籤connector的編碼
<Connector URIEncoding="utf-8" connectionTimeout="20000" port="8089" protocol="HTTP/1.1" redirectPort="8443" useBodyEncodingForURI="true"/>
2.解決方法：新增過濾器
轉自：http://bbs.csdn.net/topics/250056412
import java.io.IOException;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
public class MyFilter implements Filter {
public void destroy() {
// TODO Auto-generated method stub
}
public void doFilter(ServletRequest arg0, ServletResponse arg1,
FilterChain arg2) throws IOException, ServletException {
arg0.setCharacterEncoding("gbk");
arg2.doFilter(arg0, arg1);
}
public void init(FilterConfig arg0) throws ServletException {
// TODO Auto-generated method stub
}
}
XML：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>
org.apache.struts.action.ActionServlet
</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>f</filter-name>
<filter-class>filter.MyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>f</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
</web-app>