1. 程式人生 > >C++ 將當前系統時間轉換成標準格式的時間和時間戳

C++ 將當前系統時間轉換成標準格式的時間和時間戳

1:先將系統時間轉換成標準格式的時間,再轉成時間戳

#include "iostream"
#include "time.h"
#include "string.h"

using namespace std;

int main()
{
	time_t rawtime ; 
	struct tm * timeinfo; 
	char s[100];  
	time ( &rawtime ); 

	timeinfo = localtime ( &rawtime ); 
	time_t tick = mktime(timeinfo);
	strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", timeinfo); 

	printf("%d: %s\n", (int)tick, s);   

	int Year = timeinfo->tm_year+1900;
	int Mon = timeinfo->tm_mon+1;
	int Day = timeinfo->tm_mday;
	int Hour = timeinfo->tm_hour;
	int Min = timeinfo->tm_min;
	int Second = timeinfo->tm_sec;

	cout << Year << ":" << Mon << ":" << Day << "-" << Hour << ":" << Min << ":" << Second << endl;

	return 0;
}

其中:

int Year = timeinfo->tm_year+1900;

int Mon = timeinfo->tm_mon+1;

其餘日,時,分,秒都不變。

執行結果如下:


2:先將系統時間轉換成時間戳,再轉成標準格式的時間

#include "iostream"
#include "time.h"
#include "string.h"

using namespace std;

int main()
{
	time_t now;                                                                                                                      
	int unixTime = (int)time(&now);
	time_t tick = (time_t)unixTime;  

	struct tm tm;   
	char s[100];  
	tm = *localtime(&tick);  

	strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", &tm);  
	printf("%d: %s\n", (int)unixTime, s);   

	return 0;
}

執行結果如下: