C++ 將當前系統時間轉換成標準格式的時間和時間戳
阿新 • • 發佈:2019-01-03
1:先將系統時間轉換成標準格式的時間,再轉成時間戳
#include "iostream" #include "time.h" #include "string.h" using namespace std; int main() { time_t rawtime ; struct tm * timeinfo; char s[100]; time ( &rawtime ); timeinfo = localtime ( &rawtime ); time_t tick = mktime(timeinfo); strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", timeinfo); printf("%d: %s\n", (int)tick, s); int Year = timeinfo->tm_year+1900; int Mon = timeinfo->tm_mon+1; int Day = timeinfo->tm_mday; int Hour = timeinfo->tm_hour; int Min = timeinfo->tm_min; int Second = timeinfo->tm_sec; cout << Year << ":" << Mon << ":" << Day << "-" << Hour << ":" << Min << ":" << Second << endl; return 0; }
其中:
int Year = timeinfo->tm_year+1900;
int Mon = timeinfo->tm_mon+1;
其餘日,時,分,秒都不變。
執行結果如下:2:先將系統時間轉換成時間戳,再轉成標準格式的時間
#include "iostream" #include "time.h" #include "string.h" using namespace std; int main() { time_t now; int unixTime = (int)time(&now); time_t tick = (time_t)unixTime; struct tm tm; char s[100]; tm = *localtime(&tick); strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", &tm); printf("%d: %s\n", (int)unixTime, s); return 0; }
執行結果如下: