有name存在的是父級資料,再根據deptCode相同來匹配到同類子集的資料放到父級裡面

           this.getFatherData = this.list.filter((ele,index) => {
              console.log(ele)
               return ele.name  
            })
            console.log(this.getFatherData,4444)
            this.getFatherData.forEach((ele)=>{
              ele.children= this.list.filter((element)=>{
                return element.deptCode === ele.deptCode && !element.name
              })
            })