怎樣用js建立Form表單並提交
阿新 • • 發佈:2019-01-06
<script >
//js動態建立form 提交表單
function formSubmit(elementValue) {
var turnForm = document.createElement("form");
//一定要加入到body中!!
document.body.appendChild(turnForm);
turnForm.method = 'post';
turnForm.action = '/product/detail.htm';
turnForm.target = '_blank';
//建立隱藏表單
var newElement = document.createElement("input");
newElement.setAttribute("name","id");
newElement.setAttribute("type","hidden");
newElement.setAttribute("value",elementValue);
turnForm.appendChild(newElement);
turnForm.submit();
}
</script>
<a href="javascript:formSubmit('1')">點選我</a>