獲取兩個日期之間剩餘的天數、小時、分鐘、秒
阿新 • • 發佈:2019-01-06
本帖最後由 wuxiaodony 於 2014-8-28 16:57 編輯
例如活動截止時間是:2015/01/01 10:00:00
然後就利用當前時間對比活動截止時間,獲取剩餘的時間!
我要的不僅僅是天數,還要獲取剩餘的小時、分鐘、秒,就可以了
哪位大神路過幫幫忙,感激不盡!
現在是2004-03-26 13:31:40
過去是:2004-01-02 11:30:24
要獲得兩個日期差,差的形式為:XX天XX小時XX分XX秒
方法一:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}
方法二:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小時"+min+"分"+s+"秒");
方法三:
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;//除以1000是為了轉換成秒
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
例如活動截止時間是:2015/01/01 10:00:00
然後就利用當前時間對比活動截止時間,獲取剩餘的時間!
我要的不僅僅是天數,還要獲取剩餘的小時、分鐘、秒,就可以了
哪位大神路過幫幫忙,感激不盡!
現在是2004-03-26 13:31:40
過去是:2004-01-02 11:30:24
要獲得兩個日期差,差的形式為:XX天XX小時XX分XX秒
方法一:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}
方法二:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小時"+min+"分"+s+"秒");
方法三:
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;//除以1000是為了轉換成秒
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小時"+minute1+"分"+second1+"秒");
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