用jsonObject轉換json字元時過濾bean中空值節點
阿新 • • 發佈：2019-01-07
例：Test test = new Test();
test.setId("1");
test.setName("zhangsan");
jsonObject.fromobject(test,Test.class).toString;
輸出：{"id":"1","name":"zhangsan"}
假如不封裝name屬性，只封裝id屬性
Test test = new Test();
test.setId("1");
jsonObject.fromobject(test,Test.class).toString;
輸出：{"id":"1","name":""}
如果只輸出：{"id":"1"}
這樣的json字元，有什麼方法可以解決麼？
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public static void main(String[] args) {
Test t = new Test();
t.id = 10;
JsonConfig jsonConfig = new JsonConfig();
PropertyFilter filter = new PropertyFilter() {
public boolean apply(Object object, String fieldName, Object fieldValue) {return null == fieldValue;
}
};
jsonConfig.setJsonPropertyFilter(filter);
System.out.println(JSONObject.fromObject(t, jsonConfig).toString());
}
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