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leetcode:用兩個棧實現一個佇列 Implement Queue using Stacks

Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.
Notes:
  • You must use only standard operations of a stack -- which means only push to top
    peek/pop from topsize, and is empty operations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
    class MyQueue {
    public:
        /** Initialize your data structure here. */
        MyQueue() {
            
        }
        
        /** Push element x to the back of queue. */
        void push(int x) {
            while(!st1.empty())
            {
                st2.push(st1.top());
                st1.pop();
            }
            st1.push(x);
            while(!st2.empty())
            {
                st1.push(st2.top());
                st2.pop();
            }
        }
        
        /** Removes the element from in front of queue and returns that element. */
        int pop() {
          int top=st1.top();
          st1.pop();
          return top;
        }
        
        /** Get the front element. */
        int peek() {
            return st1.top();;
        }
        
        /** Returns whether the queue is empty. */
        bool empty() {
            return st1.empty();
        }
    private:
        stack<int> st1;
        stack<int> st2;
    };
    
    /**
     * Your MyQueue object will be instantiated and called as such:
     * MyQueue obj = new MyQueue();
     * obj.push(x);
     * int param_2 = obj.pop();
     * int param_3 = obj.peek();
     * bool param_4 = obj.empty();
     */