leetcode:用兩個棧實現一個佇列 Implement Queue using Stacks
阿新 • • 發佈:2019-01-09
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
- You must use only standard operations of a stack -- which means only
push to top
peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
class MyQueue { public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x to the back of queue. */ void push(int x) { while(!st1.empty()) { st2.push(st1.top()); st1.pop(); } st1.push(x); while(!st2.empty()) { st1.push(st2.top()); st2.pop(); } } /** Removes the element from in front of queue and returns that element. */ int pop() { int top=st1.top(); st1.pop(); return top; } /** Get the front element. */ int peek() { return st1.top();; } /** Returns whether the queue is empty. */ bool empty() { return st1.empty(); } private: stack<int> st1; stack<int> st2; }; /** * Your MyQueue object will be instantiated and called as such: * MyQueue obj = new MyQueue(); * obj.push(x); * int param_2 = obj.pop(); * int param_3 = obj.peek(); * bool param_4 = obj.empty(); */