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輸入年月日求其為本年第幾天

/*
* 程式的版權和版本宣告部分:
* Copyright (c) 2013, 煙臺大學計算機學院
* All rights reserved.
* 檔名稱:test.cpp
* 作    者:
* 完成日期:2012 年 7 月 17 日
* 版 本 號:v1.0
* 對任務及求解方法的描述部分:
* 輸入描述:無
* 問題描述:輸入一個數判斷是否為迴文數
* 程式輸出:
* 問題分析:略
* 演算法設計:略
*/
#include <iostream>
using namespace std;
int theday (int year,int month,int day);
int theyear (int year);
int main( )
{
    int year,month,day;
    cin>>year>>month>>day;
    theyear (year);
    cout<<theday (year,month,day)<<endl;
    return 0;
}
int theday (int year,int month,int day)
{
    int num1=0;
    if (year=1)
    {for (int i=1;i<month;i++)
    {
            switch (i)
            {case 1:num1=num1+31;break;
            case 3:num1=num1+31;break;
            case 5:num1=num1+31;break;
            case 7:num1=num1+31;break;
            case 8:num1=num1+31;break;
            case 10:num1=num1+31;break;
            case 12:num1=num1+31;break;
            case 2:num1=num1+29;break;
            case 4:num1=num1+30;break;
            case 6:num1=num1+30;break;
            case 9:num1=num1+30;break;
            case 11:num1=num1+30;break;
            }
}
}
    else
    {for (int i=1;i<month;i++)
        {switch (i)
            {case 1:num1=num1+31;break;
            case 3:num1=num1+31;break;
            case 5:num1=num1+31;break;
            case 7:num1=num1+31;break;
            case 8:num1=num1+31;break;
            case 10:num1=num1+31;break;
            case 12:num1=num1+31;break;
            case 2:num1=num1+28;break;
            case 4:num1=num1+30;break;
            case 6:num1=num1+30;break;
            case 9:num1=num1+30;break;
            case 11:num1=num1+30;break;
            }
    }
    }
    num1+=day;
    return num1;
}
int theyear (int year)
{
    if(year%400 == 0 || year%100 != 0 && year % 4 == 0)
    year=1;
    else
    year=0;
    return year;
}