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一個簡單的時間和日期程式

#include <iostream>
using namespace std;


struct Date{
	int y;  // year
	int m;  //month
	int d;  //day
};	

bool is_leap(int y)
{
	return (y%4==0 &&y%109!=0 || y%400==0);
}

int days_of_month(int y, int m)
{
	int day[12] = {31,0, 31, 30, 31,30, 31, 31, 30, 31, 30, 31};

	if (m!=2) return day[m-1];
	else return (28 + is_leap(y));
} 


int days_of_date(Date d)
{
	int days = 0;
	for (int y=1; y<d.y; y++)
		days = days + 365 + is_leap(y);
	for (int m=1; m<d.m; m++)
		days = days + days_of_month(d.y, m);
	
	days = days + d.d;

	return days;
}


int main()
{
	Date d1;
	Date d2;

	cout << "請輸入兩個日期:(yyyy mm dd)" << endl;
	cin >> d1.y >> d1.m >> d1.d;
	cin >> d2.y >> d2.m >> d2.d;

	int days1 = days_of_date(d1);
	int days2 = days_of_date(d2);
	cout <<"difference:" << days2 - days1 << endl;
	cout << "weekend:" << days1%7 << ',' << days2%7 << endl; 


	return 0;
}