一個簡單的時間和日期程式
阿新 • • 發佈:2019-01-24
#include <iostream> using namespace std; struct Date{ int y; // year int m; //month int d; //day }; bool is_leap(int y) { return (y%4==0 &&y%109!=0 || y%400==0); } int days_of_month(int y, int m) { int day[12] = {31,0, 31, 30, 31,30, 31, 31, 30, 31, 30, 31}; if (m!=2) return day[m-1]; else return (28 + is_leap(y)); } int days_of_date(Date d) { int days = 0; for (int y=1; y<d.y; y++) days = days + 365 + is_leap(y); for (int m=1; m<d.m; m++) days = days + days_of_month(d.y, m); days = days + d.d; return days; } int main() { Date d1; Date d2; cout << "請輸入兩個日期:(yyyy mm dd)" << endl; cin >> d1.y >> d1.m >> d1.d; cin >> d2.y >> d2.m >> d2.d; int days1 = days_of_date(d1); int days2 = days_of_date(d2); cout <<"difference:" << days2 - days1 << endl; cout << "weekend:" << days1%7 << ',' << days2%7 << endl; return 0; }