第一種方法：

select substr(t,1,instr(t,',',1)-1) from (
select substr(s,instr(s,',',1,rownum)+1)||',' as t,rownum as d ,instr(s,',',1,rownum)+1 from (
select ',tt,aa,bb'  as s from dual
)connect by instr(s,',','1',rownum)>1)

查詢結果：

    SUBSTR(T,1,INSTR(T,',',1)-1)
1 tt
2 aa
3 bb

第二種

select substr(t,1,instr(t,',',1)-1)   from (
select substr(s,instr(s,',',1,rownum)+1) as t,rownum as d ,instr(s,',',1,rownum)+1 from (
select ',tt,aa,bb,' 

備註：主要是用了connect by的迴圈作用