實現效果:

知識運用：

　　Process類的Start方法

實現代碼：

        private void button1_Click(object sender, EventArgs e)
        {
            OpenFileDialog open = new OpenFileDialog();
            open.Filter = "EXE文件(*.exe)|*.exe";
            if (open.ShowDialog() == DialogResult.OK)
                textBox1.Text = open.FileName;
        }
        private void button2_Click(object sender, EventArgs e)
        {
            System.Diagnostics.Process.Start(textBox1.Text);
        }

調用外部EXE文件