JObject job = (JObject)JsonConvert.DeserializeObject(strBuff);

foreach (var item in job["subjects"]) { subjects subj = new subjects(); rating rat = new rating { max = item["rating"]["max"].ToString(), average = item["rating"]["average"].ToString(), min = item["rating"]["min"].ToString(), stars = item["rating"]["stars"].ToString() }; subj.rating = rat; subj.title=item["title"].ToString(); images img = new images { large = item["images"]["large"].ToString(), medium = item["images"]["medium"].ToString(), small = item["images"]["small"].ToString() }; subj.images=img; subj.collect_count=item["collect_count"].ToString(); subj.original_title=item["original_title"].ToString(); subj.subtype=item["subtype"].ToString(); subj.id=item["id"].ToString(); subj.alt=item["alt"].ToString(); lstsub.Add(subj); }

1、先引用一下標頭檔案  using Newtonsoft.Json.Linq;

//將反序列化的資料強轉成JObject或JArry

JObject job = (JObject)JsonConvert.DeserializeObject(strBuff);

2、然後就可以像DataTable一樣取值了