題目標題: 計算兩個字串的最大公共字串的長度,字元不區分大小寫
阿新 • • 發佈:2019-02-01
private static int getMaxSame(String first0,String second0) { String first = first0.toLowerCase(); String second = second0.toLowerCase(); int fLen = first.length(); int sLen = second.length(); int d = (fLen <= sLen) ? fLen : sLen; String min = null; String max = null; String target = null; if (fLen <= sLen) { min = first; max = second; } else { min = second; max = first; } for (int i = d; i >= 1; i--) { for (int j = 0; j <= min.length() - i; j++) { target = min.substring(j, j + i); for (int k = 0; k <= max.length() - i; k++) { if (max.substring(k,k + i).equals(target)) { return i; } } } } return 0; }
下面是測試程式碼,一定要這樣輸入,兩個字串用空格隔開,然後用split方法讀取待處理的兩個字串:
public static void main(String[] args) {
Scanner sca = new Scanner(System.in);
String strFirst = sca.nextLine();
String[] strArray = strFirst.split(" ");
System.out.println(getMaxSame(strArray[0], strArray[1]));
}