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jquery each報 Uncaught TypeError: Cannot use 'in' operator to search for錯誤

在寫前端的時候用jquery來遍歷後臺傳來的json陣列時候遇到這個錯誤:Uncaught TypeError: Cannot use 'in' operator to search for。後來查到原因是因為:一部分瀏覽器後端傳過來的是json物件,但是我們前端是需要Javascript的物件,所以需要做個轉換JSON.parse() or jQuery $.parseJSON

Review a simple jQuery example to loop over a JavaScript array object.

var json = [
	{"id":"1","tagName":
"apple"}, {"id":"2","tagName":"orange"}, {"id":"3","tagName":"banana"}, {"id":"4","tagName":"watermelon"}, {"id":"5","tagName":"pineapple"} ]; $.each(json, function(idx, obj) { alert(obj.tagName); });

Above code snippet is working fine, prompts the “apple”, “orange” … as expected.

Problem : JSON string

Review below example, declares a JSON string (enclosed with single or double quotes) directly.

var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
{"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
{"id":"5","tagName":"pineapple"}]';
	
$.each(json, function(idx, obj)
{ alert(obj.tagName); });

In Chrome, it shows following errors in console :

Uncaught TypeError: Cannot use 'in' operator to search for '156' 
in [{"id":"1","tagName":"apple"}...

Solution : Convert JSON string to JavaScript object

To fix it, converts it to Javascript object via standard JSON.parse() or jQuery $.parseJSON.

var json = '[{"id":"1","tagName":"apple"},{"id":"2","tagName":"orange"},
{"id":"3","tagName":"banana"},{"id":"4","tagName":"watermelon"},
{"id":"5","tagName":"pineapple"}]';
	
$.each(JSON.parse(json), function(idx, obj) {
	alert(obj.tagName);
});

//or 

$.each($.parseJSON(json), function(idx, obj) {
	alert(obj.tagName);
});
Note
Most web applications will return JSON formatted string directly, you need to convert it to JavaScript object before parse it with jQuery. 參考連結:http://www.mkyong.com/jquery/jquery-loop-over-json-string-each-example/